So if you need to solve for the vertex angle $\theta$, we have that $\theta = 180 - 2x$.Īlso note, to find an angle, given none of the angles are known, you can to use the lengths of the sides of the triangle to solve for the base angles and/or vertex, and can use the Law of Cosines to do that. The two angles opposite the legs are equal and are always. \dfrac\right) = 64.8$$Įach base angle, let's call them each of measure $x$, plus the vertex angle add up to $180$. Every isosceles triangle has an axis of symmetry along the perpendicular bisector of its base. Therefore, the area of the triangle ADB is 1/2 × 3 × 4 3 × 2 6 cm 2. The formula for the area of a triangle is 1/2 × b × h. In triangle ADB, base (b) 3 cm, height (h) 4 cm.
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